Question

If f(x) = 1/9x - 2, what is f^-1 (x)

Answer 1

still need help?

Answer 2

rearrange equation to solve for x
switch x and y to get the inverse function

Let y = 1/(9x - 2)

rearrange to solve for x
9x - 2 = 1/y
9x = 1/y + 2
x = 1/(9y) + 2/9

switch x and y
y = 1/(9x) + 2/9

f⁻¹(x) = 1/(9x) + 2/9
=====
Let y = (1/9)x - 2.

(1/9)x = y + 2
x = 9y + 18

g(x) = 9x + 18 <- Your final answer

Answer 3

how do you know that it's 1/(9x-2) ?

Could be (1/9x) - 2 or (1/9)x - 2