Question

help please
Solve 64^x = 16^x−1.

x = −2
x = −1
x = negative 1 over 4
x = negative 1 over 3

Answer 1

HI!!

Answer 2

since \[4^2=16\] and \[4^3=64\] this is the same as
\[\huge4^{3x}=4^{2(x-1)}\]