A particle moving uniformly along the x axis is located at 9.27 m at 1.12 s and at 4.6 m at 3.04 s. Find its displacement during this time interval.

Question

kropot72 · Answer

The particle moves from right to left, therefore we have negative displacement, given by:
-(9.27 - 4.6)m

anonymous · Answer

Ok, so that means the answer is -4.67.

kropot72 · Answer

You are correct.

anonymous · Answer

Yey:) and if they ask for velocity, then would i just find the slope? Like: (9.27-4.6)/(1.12-3.04)

anonymous · Answer

And would avg. speed be the same as velocity for this question?

kropot72 · Answer

Velocity is a vector quantity. Therefore it is given by:
$$\large v=\frac{-4.67}{(3.04-1.12)}\ m/s$$

anonymous · Answer

Ohh, I see. thank you!

kropot72 · Answer

You're welcome :)

anonymous · Answer

How about average speed? Would the average speed differ from the velocity?

kropot72 · Answer

Speed is a scalar quantity, therefore the negative sign does not apply.