Question

A teacher gave her class two exams; 60% of the class passed the second exam, but only 48% of the class passed both exams. What percent of those who passed the second exam also passed the first exam?

Answer 1

80%
12%
30%
48%

Answer 2

@mathmate

Answer 3

I got 80% ??

Answer 4

correct!
P(B)=0.60
P(A\(\cap\)B)=0.48
P(A|B)=P(A\(\cap\)B)/P(B)=0.48/0.60=0.80=80%

Answer 5

Thanks!

Answer 6

You're welcome! :)