Question

ABCD is a trapezium. BC = 4 cm, Angle ABC = 30 degree, CD = 6 cm. Area of triangle ACB = 8 cm sq. Then the area of trapezium ABCD is?

Answer 1

Area of trapezium is just 1/2* sum of its parallel sides * height
right?

so we need AB and height CE


CE can be found using 30 -60 -90 rule

Answer 2

AB can be found since area ig given and height we just found

Answer 3

Answer is coming out to be 14.8 while the actual answer is 14.

Answer 4

CE = 2

16 = 2*AB

AB = 8

Area = 1/2(8+ 6)* 2

Answer 5

which indeed = 14

Answer 6

how did you get 14.8 ? :)

Answer 7

ask if any doubts...

Answer 8

How come CE = 2 ?

Answer 9

@hartnn ?

Answer 10

"side opposite to 30 degree is half the hypotenuse"