OpenStudy (anonymous):

ABCD is a trapezium. BC = 4 cm, Angle ABC = 30 degree, CD = 6 cm. Area of triangle ACB = 8 cm sq. Then the area of trapezium ABCD is?

3 years ago
OpenStudy (anonymous):

|dw:1442153457354:dw|

3 years ago
hartnn (hartnn):

Area of trapezium is just 1/2* sum of its parallel sides * height right? so we need AB and height CE |dw:1442153898438:dw| CE can be found using 30 -60 -90 rule

3 years ago
hartnn (hartnn):

AB can be found since area ig given and height we just found

3 years ago
OpenStudy (anonymous):

Answer is coming out to be 14.8 while the actual answer is 14.

3 years ago
hartnn (hartnn):

CE = 2 16 = 2*AB AB = 8 Area = 1/2(8+ 6)* 2

3 years ago
hartnn (hartnn):

which indeed = 14

3 years ago
hartnn (hartnn):

how did you get 14.8 ? :)

3 years ago
hartnn (hartnn):

ask if any doubts...

3 years ago
OpenStudy (anonymous):

How come CE = 2 ?

3 years ago
OpenStudy (anonymous):

@hartnn ?

3 years ago
hartnn (hartnn):

|dw:1442155869078:dw| "side opposite to 30 degree is half the hypotenuse"

3 years ago