Question

Please help!

Solve for x.

−ax + 4b > 9

A) x > the quantity 4 times b minus 9 all over a

B) x < the quantity 9 minus 4 times b all over a

C) x < the quantity negative 4 times b plus 9 all over negative a

D) x > the quantity 4 times b plus 9 all over negative a

Answer 1

-ax + 4b > 9 --- subtract 4b from both sides
-ax > -4b + 9 -- divide by -a and change inequality sign
x < (-4b + 9) / -a
OR
x < 4b/a - 9/a