Question

An electron, starting from rest and moving with a constant acceleration, travels 2.0 cm in 5.0 ms. What is the magnitude of this acceleration?

Answer 1

\[d=v_0t+\frac{ 1 }{ 2 }at^2\]
\[2\times10^{-2}m=0+\frac{ 1 }{ 2 }a(5\times10^{-3}s)^2\]

Answer 2

I just noticed that the answer has to be in km/s^2

Answer 3

It's the same deal, just convert 2 cm to km