Question

Assume that you have 6 dimes and 4 quarters (all distinct), and you select 3 coins.
(1) In how many ways can the selection be made?


(2) In how many ways can the selection be made if all the coins are dimes?


(3) In how many ways can the selection be made if you select 2 dimes and 1 quarter?


(4) In how many ways can the selection be made so that at least 2 coins are dimes?

Answer 1

1) C(6,3) or C(4,3)

Answer 2

@ganeshie8

Answer 3

so 1)24?

Answer 4

Im sorry, you're right

Answer 5

:)

Answer 6

I was looking at the wrong values

Answer 7

I think u can figure this out by your own from now

Answer 8

im right on what?

Answer 9

on the frist one