Question

Use the quadratic formula to solve the equation.
-2x^2+3x+5=0

Answer 1

Compare your quadratic equation with \(ax^2+bx+c=0\)
find \[a=...?\\b=...?\\c=...?\\\] \[ \\ \sqrt{b^2-4ac}=...?\]
then the two roots of x are:
\(\huge{x_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)

Answer 2

somethings not coming up correctly :(. I tried plugging everything in.

Answer 3

can you plz show your work?

Answer 4

\[\sqrt{3x^2-4(2x^2*5)}\]

Answer 5

okk...we can't have x in the values of a,b,c