Question

x2 + 5x = 14

Answer 1

7X=14
x= 2

Answer 2

it's not 2x+5x
\[\huge\rm x^2+5x=14\] set it equal to zero move 14 to the right side
so subtract 14 both sides \[\huge\rm x^2+5x-14=0\]now find two number when you multiply them you should get `product of AC` and when yo add or subtract them you should get the middle term


a , b ,c are \[\huge\rm Ax^2+Bx+C=0\]
a=leading coefficient
b=middle term
c=constant term