Question

http://prntscr.com/8gesl4

Help would be great, thanks.

Answer 1

i would say D but that is my opinion i would ask someone else

Answer 2

for there opinion

Answer 3

Mmm, multiplying across seemed to have happened when the "u" was backwards, so would i have to do the opposite ? Or mmm idk i get lost with these "u's"

Answer 4

best one to ask would be steve816

Answer 5

oh ok thanks @dm91 for your input though, and um @steve816 mind lending a quick hand with this problem, thanks.

Answer 6

anytime

Answer 7

Ah algebra 2.. such a pain in my butt. Okay, let me see if I can type all of this out real quick because I just finished this class last year.

Answer 8

yup such a pain ! and, oh ok
thanks !

Answer 9

So basically what we have here are intersections and unions. The intersection (upside down U) a set that contains elements that are common to both sets. Then a union (U) is a set that contains all elements of those 2 sets. If two events (A & B) are independent, then P(A [upside U] B) = P(A) times P(B). P (A U B) = P(A) + P(B) - P(A [upside down U] B). Since they give you P(A), P(B), and what P(A U B) is. It's all in the matter of plugging it in the equation.

Answer 10

sooo.... it will be 2/3+4/5-8/15=P(AdownwarduB)

Answer 11

i ended up with 14/15, lets give it ago ! see how it goes.

Answer 12

@rheaanderson341 got it correct ! thanks for the help !

Answer 13

Grr slow Google Chrome. Always welcome though! :)