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y+8x= 2x squared +1 solve using complete square
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@freckles
Can you screenshot the question?
no i can't sorry
I'm not sure what the question is asking.... @zzr0ck3r ??
y+8x= 2x squared +1
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y+8x= 2x squared +1 solve using complete the square
y+8x= 2x^1?
y+8x= 2x^2 +1?
is that the question?
yes
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@zzr0ck3r im not sure can u help with this one please? :)
\[y=2x^2-8x+1\] now you may go ahead and complete the square
i got x^2 -8x+32=15 not sure how to factor that
\[x^2+ax=0\] we can do the following \[x^2+\frac{ 2ax }{ 2 } + \left( \frac{ a }{ 2 } \right)^2-\left( \frac{ a }{ 2 } \right)^2=0\]
That's completing the square
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how do we get the x values
|dw:1442277314632:dw|
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