I have half way solved this question already But wanted some clarification think your up to it?
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OpenStudy (some.random.cool.kid):
One solution to a quadratic equation is x equals start fraction negative six plus 18 i over two end fraction full stop What is the solution in simplified standard form, x = a + bi, if a and b are real numbers?
OpenStudy (anonymous):
@Nnesha
OpenStudy (some.random.cool.kid):
I believe that this is x = -3 + 9i?
OpenStudy (some.random.cool.kid):
@paki @pooja195 @Nnesha @nincompoop @ganeshie8
OpenStudy (some.random.cool.kid):
The complex solution to a quadratic equation is x equals start fraction negative 12 plus or minus square root of negative 180 end square root over six end fraction full stop Write this solution in standard form, x = a ± bi, where a and b are real numbers.
this one I have too but also want to know if i got it correct?
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OpenStudy (some.random.cool.kid):
I have -2 + or - i sqrt of 5
OpenStudy (some.random.cool.kid):
@Compassionate
OpenStudy (some.random.cool.kid):
Finally I have one that needs explaining and I have heck of a clue what this even is...
OpenStudy (some.random.cool.kid):
this is last one...
OpenStudy (some.random.cool.kid):
@Abhisar
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