Mathematics
14 Online
OpenStudy (pinklion23):
32-6x+7x=(-15)+28
solve for x X=
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jagr2713 (jagr2713):
Hey what do you think we do first?
OpenStudy (pinklion23):
subtract 32 from both sides
jagr2713 (jagr2713):
Yes you can but don't you want to add like terms first?
OpenStudy (pinklion23):
oh yeah i forget so 13x
jagr2713 (jagr2713):
you forgot the negative sign.
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OpenStudy (pinklion23):
oh ok so 32-(-13x)= (-15)+28?
jagr2713 (jagr2713):
nope
-6+7x= 1
OpenStudy (pinklion23):
so then x=1
jagr2713 (jagr2713):
Yes so we have
32+x=(-15)+28 left right?
so what next
OpenStudy (pinklion23):
then we do32- 28 so then it would be 4+x=(-15)
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jagr2713 (jagr2713):
good what next?
OpenStudy (pinklion23):
the x=-19?
jagr2713 (jagr2713):
Correct :D
OpenStudy (pinklion23):
wow thx so much can you help me with some more?
jagr2713 (jagr2713):
Of course :D
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OpenStudy (pinklion23):
-4X+5(X-2)=-16+10
jagr2713 (jagr2713):
what do we do first?
OpenStudy (pinklion23):
-16+10?
jagr2713 (jagr2713):
yea you can so we get -6
jagr2713 (jagr2713):
-4x+5(x-2)=-6
whats next?
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OpenStudy (pinklion23):
yeah
OpenStudy (pinklion23):
um then we do -6-2?
jagr2713 (jagr2713):
Nope
when we have a number like 5(x-2) we distribute. Do you how to distribute ?
OpenStudy (pinklion23):
so then we do (x*5)-(2*5)
jagr2713 (jagr2713):
Yes like this|dw:1442341177921:dw|
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jagr2713 (jagr2713):
So we just multiply everything inside that parenthesis
OpenStudy (pinklion23):
yeah
jagr2713 (jagr2713):
so now we got
-4x+5x-10=-6
whats next
OpenStudy (pinklion23):
then we have 1x-10=-6
jagr2713 (jagr2713):
It's not 1x
x=1 so u don't need to put the 1
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OpenStudy (pinklion23):
the we add -10 to -6
OpenStudy (pinklion23):
?
OpenStudy (pinklion23):
so X=1
jagr2713 (jagr2713):
you got that?
x=1
you out
1x-10=-6
but x already is 1 so u don't need to put the 1x just
x-10=-6
OpenStudy (pinklion23):
ok so X = -16
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OpenStudy (pinklion23):
or -4
jagr2713 (jagr2713):
nope -6+10?
jagr2713 (jagr2713):
positive 4 :D
OpenStudy (pinklion23):
oh ok thx
jagr2713 (jagr2713):
Yep Anytime :D
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OpenStudy (pinklion23):
i have two more can you help me with them
jagr2713 (jagr2713):
ummm ill see what i can do :D