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Mathematics 10 Online
OpenStudy (anonymous):

A tennis ball is thrown into the air with velocity 56 feet per second. It's height in feet t seconds later is given by f(t)=56t-16t^2 A.) find the average velocity for the time period beginning when t=2 seconds and lasting.... i. 0.5 seconds. ii. 0.1 iii. 0.05. iv. 0.01 B.) using your work in part a, estimate the instantaneous velocity when t=2

OpenStudy (amistre64):

part A is just finding the slope between 2 points; namely t=2 and t=2+d part B, as the value of d gets smaller, what is the slope look like its getting closer to?

OpenStudy (anonymous):

I'm lost

OpenStudy (irishboy123):

using \(f(t)=56t-16t^2\) for i) , first calculate f(2.5) - f(2)

OpenStudy (irishboy123):

that will give you the difference in height between those two points in time yes?!

OpenStudy (irishboy123):

then divide your answer by 0.5 0.5s is how long it too to move between those points the calculation gives you an approximation of speed at t = 2. those are the steps

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