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Find the arc length of y=x^(2/3) for 0
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\[\int_{}^{}ds\implies \int_{}^{}\sqrt{(x')^2+(y')^2}~dt\]
of instead of dt, we can do with dx, and let x'=1
what are you getting for your setup?
im getting this \[\int\limits_{0}^{1} \sqrt{(1)^2 + (x^\frac{ 2 }{ 3 })^2} dx\]
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oh wait
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