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If f(2)=3 and f'(2)=-1, find an equation of the tangent line when x=2. a) y-3=2(x+1) b) y-2=3(x+1) c) y+1=2(x-2) d) y-3=-(x-2) e) y+1=-(x-2)
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(x,y) = (2,3) m = -1
That's the information they gave us ^
Remember how to plug it into point-slope form? :)
Oh! i wasn't sure how to connect that! yes i do, thanks!
yay \c:/
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answer is d right?
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