if f(x)= x+3 / 4 (x+3 over 4), what is the equation for f^–1(x)?
a. f^–1(x) = 4(x - 3)
b. f^–1(x) = 4x + 3
c. f^–1(x) = 4(x + 3)
d. f^–1(x) = 4x - 3

Question

if f(x)= x+3 / 4 (x+3 over 4), what is the equation for f^–1(x)? 
a. 	f^–1(x) = 4(x - 3)
b. f^–1(x) = 4x + 3
c. f^–1(x) = 4(x + 3)
d. f^–1(x) = 4x - 3

jhannybean · Answer

$$f(x)=\frac{x+3}{4\left(\dfrac{x+3}{4}\right)}$$Is this your problem?

jdoe0001 · Answer

$\bf f(x)={\color{blue}{  y}}=\cfrac{{\color{brown}{  x}}+3}{4}
\quad \textit{do the switcharoo baby}\quad {\color{brown}{  x}}=\cfrac{{\color{blue}{  y}}+3}{4}\impliedby f^{-1}(x)$

anonymous · Answer

$$f(x) = \frac{ x+3 }{ 4 }$$

campbell_st · Answer

so the function is 

$$y = \frac{x + 3}{4}$$

to find the inverse swap x and y 

$$x = \frac{y + 3}{4}$$

now make y the subject of the equation

jhannybean · Answer

Oh I simply read it wrong, whoops.