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if f(x)= x+3 / 4 (x+3 over 4), what is the equation for f^–1(x)? a. f^–1(x) = 4(x - 3) b. f^–1(x) = 4x + 3 c. f^–1(x) = 4(x + 3) d. f^–1(x) = 4x - 3
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\[f(x)=\frac{x+3}{4\left(\dfrac{x+3}{4}\right)}\]Is this your problem?
\(\bf f(x)={\color{blue}{ y}}=\cfrac{{\color{brown}{ x}}+3}{4} \quad \textit{do the switcharoo baby}\quad {\color{brown}{ x}}=\cfrac{{\color{blue}{ y}}+3}{4}\impliedby f^{-1}(x)\)
\[f(x) = \frac{ x+3 }{ 4 }\]
so the function is \[y = \frac{x + 3}{4}\] to find the inverse swap x and y \[x = \frac{y + 3}{4}\] now make y the subject of the equation
Oh I simply read it wrong, whoops.
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