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find a formula fro F^-1(x) and state its domain f(x)=5x-4
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\(y=5x-4\) Switch x and y \(x=5y-4\) Solve for x
sorry solve for y
the domain of \(f^{-1}(x)\) is the range of \(f(x)\). This is linear, so that's all real numbers
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