Question

A basketball player gets 2 free-throw shots when she is fouled by a player on the opposing team. She misses the first shot 40% of the time. When she misses the first shot, she misses the second shot 5% of the time. What is the probability of missing both free-throw shots?

Answer 1

?

Answer 2

multiply

Answer 3

Let A be the event 'misses the first shot' and let B be the event 'misses the second shot.
P(A) = 0.4
P(B|A) = 0.05
\[\large P(A \cap B)=P(A) \times P(B|A)\]

Answer 4

.02 ?

Answer 5

Correct.

Answer 6

is hat the answer

Answer 7

Yes, that value is the probability of missing both free-throw shots.