Question

Could someone please check my work? I'm trying to solve for G in the following equation (click to see).

Answer 1

i can try

Answer 2

\[n(\frac{ 100 }{ M })^{2}= 2^{G-1}\]

Answer 3

im not sure i depends on what it is ...

Answer 4

it*

Answer 5

sorry im not sure... check with someone more experienced than I @Nnesha

Answer 6

My solution:

\[G=\frac{ \ln(25(\frac{ 100 }{ M })^{2}) }{ \ln(2) }+1\]

Answer 7

I got this. Is n supposed to be 25?