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OpenStudy (anonymous):
Simplified version of x+2/y-3 + 3x-1/y-3.... is the corrrect answer 4x+1/y-3 ??? Medals
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jimthompson5910 (jim_thompson5910):
the original expression is this right?
\[\Large \frac{x+2}{y+3} + \frac{3x-1}{y+3}\]
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
ya thats right
jimthompson5910 (jim_thompson5910):
you have the correct answer assuming you meant to write \[\Large \frac{4x+1}{y+3}\]
jimthompson5910 (jim_thompson5910):
sorry for some reason, I wrote "y+3" when it should be "y-3". My bad
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OpenStudy (anonymous):
Thank you both!! And its okay thank you for your help!
jimthompson5910 (jim_thompson5910):
no problem
OpenStudy (anonymous):
Did i get this one right too? 3/x+1 + 4/x+1.... the answer is 7/x+1 ??
jimthompson5910 (jim_thompson5910):
yes you did
jimthompson5910 (jim_thompson5910):
Nice job
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jimthompson5910 (jim_thompson5910):
use parenthesis to indicate you are dividing by all of "x+1"
`3/x+1` is NOT the same as `3/(x+1)`
jimthompson5910 (jim_thompson5910):
\[\Large 3/x + 1 = \frac{3}{x} + 1\]
\[\Large 3/(x + 1) = \frac{3}{x+1}\]
OpenStudy (anonymous):
Im so sorry I didn't know! I'm new to this so I'm learning
jimthompson5910 (jim_thompson5910):
that's ok
OpenStudy (anonymous):
Am i correct for this problem also?
5x^2 - x(x-3)
= 4x^2- 3x ??
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jimthompson5910 (jim_thompson5910):
you distributed incorrectly
jimthompson5910 (jim_thompson5910):
|dw:1442454918377:dw|
jimthompson5910 (jim_thompson5910):
|dw:1442454929560:dw|
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