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Mathematics 13 Online
OpenStudy (sissyedgar):

Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 4 h, and Car B traveled the distance in 4.5 h. Car B traveled 5 mph slower than Car A. How fast did Car B travel? mph

OpenStudy (anonymous):

i hate word problems don't you?

OpenStudy (sissyedgar):

Yass!

OpenStudy (anonymous):

distance is rate times time, so \[D=4\times R=4.5\times( R-5)\]

OpenStudy (anonymous):

we can solve \[4R=4.5(R-5)\] for R

OpenStudy (sissyedgar):

wait 1 sec...

OpenStudy (sissyedgar):

R = 45 rite?

OpenStudy (anonymous):

yeah! but we are not done

OpenStudy (sissyedgar):

mk

OpenStudy (anonymous):

i had \(R\) as the rate of the faster car, so the rate of the slower car is \(45-5=40\)

OpenStudy (sissyedgar):

right! Ty Satellite!

OpenStudy (anonymous):

yw

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