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PLEASE HELPP MEDALLS. What are the roots of -12x^2+11x-3=0
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you can complete the square or use the quadratic formula
do you know how to do either?
Yeah let me try the quadratic formula and see if i get the right answer
Yeah...idk how to do it.
\(ax^2+bx+c=0 \iff x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a} \) for you \[a=-12 \\ b=11\\c=-3\]
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Yeah i got that ..but the answer choices have the letter i in them and idk where the i comes from
oh that is complex numbers used when you get negative square root
Would the answer be -11 plus or negative i×square root of 15 over 12?
I meant square root of 23 over 24
basically \[i = \sqrt{-1}\]
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\[e.g.\sqrt{-11}=\sqrt{11}i\]
I understand thank you!
no worries :)
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