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area of rectangle=w*l given- area=x^2 +40x+300 so w*l =x^2 +40x +300 \[w*l=x^2 +10x+30x+400\]\[w*l=x(x+10)+30(x+10)\]\[w \times l =(x+10)(x+30)\]comparing u get w=x=10 and l=x+30
@surjithayer
length=x+30=20+30=50 width=x+10=20+10=30 area=50*30=1500 or just plug x=20 in the given area.
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