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Suppose that on a hot and sticky afternoon in the spring, a tornado passes over the high school. If the air pressure in the lab (volume of 180 m3) was 1.1 atm before the storm and 0.85 atm during the storm, to what volume would the laboratory try to expand in order to make up for the large pressure difference outside?
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use boyle's law:\[P_1*V_1 = P_2*V_2\]
Would it be around 230m^3
That's around what I get
Alright. Thank you.
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