Question

1.Solve for p
3(p+q)=p

2.solve for b then find the value of b when a=3
4a=2b-7

3. Solve for r
D=rt

4. Find the width of a rectangle with a perimeter of 90 and the length of 15

Answer 1

1. 3p-p=-3q therefore p=-(3/2)q

2. 2b-7=4a therefore 2b=4a+7 therefore b=2a+7/2
in order to see how much is b when a=3, just plug in a=3, and we get b=2(3)+7/2=19/2

3. r=D/t

4. perimeter=2(length)+2(width) therefore 2width=perimeter-2(length). Divide both sides by 2 and plug in numbers:
width= 90/2-15=30

Answer 2

Thank you 👌🏻😉

Answer 3

medal?