Question

Find a number 'a' such that the limit exists.
lim -> -2 (3x^2 + ax + a + 3)/(x^2+x-2)

Answer 1

I know that this factors to
lim -> -2 (3x^2 + ax + a + 3)/(x-1)(x+2)

Answer 2

(3x^2 + ax + a + 3)/(x+2) = (x^2+x-2)

so that the top also has x+2 factor to cancel out

Answer 3

solve that for a, and that is your value of a.

Answer 4

I have to go back to my hateful physics.... cu