Question

Three coins are tossed. Find the probability of tossing each of the following events:
1. Three heads.
Answer:
2. Two heads and a tail.
Answer:

3. At least one tail.
Answer:

4. At least two heads.
Answer:

Answer 1

S={HHH,HTH,HTT,HHT,TTT.TTH,THT,THH}
1-P(A)=n(A)/n(s)
P(A)=1/8 (only HHH)

Answer 2

okay so how about the others?

Answer 3

is #2 3/8

Answer 4

yes. HTH,HHT,THH

Answer 5

is 3) 7/8 and 4) 1/2

Answer 6

yes.