the solutions to the inequalities 0 ≤ x ≤ 2, 0 ≤ y ≤ 1, and y ≤ -(1/2x) + (3/2) form a polygonal region in the plane. How many sides does this polygon have?

Question

anonymous · Answer

Hi ... I can help you with this.  Let's take each piece separately.  Do you know what the graph of  $$0 \le x \le 2$$ looks like?

anonymous · Answer

(You could use the "Draw" button to draw it...)

anonymous · Answer

Hint:  you want all the points $$(x,y)$$ that have x-values between 0 and 2.

anonymous · Answer

I'm new here ... is there any way of knowing if someone is still there wanting help with a question, or if they've left?

anonymous · Answer

i do not see the draw button. And yes i do need help please.

anonymous · Answer

Sorry -- I thought you were gone.  Are you still here?  Do you still want help with this?