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Find d2^y/dx^2 in terms of x and y.
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\[x ^{2}y ^{2}-8x=2\]
2xy^2+x^2(2y)dy/dx-8=0
I already have the first derivative figured out, I don't know how to find the second though
just change the sides take evrything to right side except x^2(2y)dy/dx
do I just plug in x^2y^2−8x into the derivative of d2^y/dx^2?
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nope u do like this |dw:1442671687613:dw|
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