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A graph of a quadratic function is shown below. graph of y equals negative 2 times x squared plus 40 x plus 600 What is the vertex of the parabola shown? (30, 0) (800, 10) (0, 600) (10, 800)
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\[\huge\rm y=-2x^2+40x+600\] formula to find x-coordinate of the vertex \[\huge\rm x= -\frac{ b }{ 2a }\] then substitute x for its value into the original equation to find y-coordinate \[\huge\rm Ax^2+Bx+C=0\] a=leading coefficient b=middle term
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