help?
Post the question where you put "help?"
and ideas?
my answer is b. but im confused.
Yeah, B is the answer. What confuses you?
almost, you do want to square root both sides, but when we induce the square, we get a positive and negative answer.
the answer is not B
oh right
If 16 is X squared, then X is the square root of 16. Ok, now I'm confused.
so it would be c yea?
I swear it's B!
i.e. \[(-4)^2=(-4)(-4)=16=4*4=4^2=\]
Confusion is occuring.
I don't know what I'm doing it appears. I'm just gonig to go because this seems to be much more complicated than I thought :I
the answer to \(x=\sqrt{16}\) is \(x=4\) The answer to \(x^2=16\) is \(x=\pm 4\)
@FitzIncorporated it is a common mistake. when we write \(\sqrt{something}\) we mean the positive square root(just like if we write 1). But when we induce a square (when we take square root of both sides) we get two answers. In other words, the square root of 4 is 2 but there are two answers if I ask you what number squared is 4, they are 2 and -2
so its c? its lagging a bit
C
okTy :)
@zzr0ck3r Thank you :)
for sure :)
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