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I need help with inverses 1.g(x)=2/5(x-1) 2.h(x)=(3x)^2+8
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g(x) and h(x) is same as y variable so replace g(x) with y \[\huge\rm \color{ReD}{y}=\frac{ 2 }{ 5 }(\color{blue}{x}-1)\] to find inverse `switch x and y` \[\huge\rm \color{blue}{x}=\frac{ 2 }{ 5 }(\color{red}{y}-1)\] now solve the equation for y same steps for 2nd question
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