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Sketch the curve in polar coordinates r^2 = 16 sin 2(theta)
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@Hero @Shalante @IrishBoy123
It's best to use a polar graph to plot the points
umm I think i might know what i have to do
but i just dont know is that is right
I mean i trying to find the endpoints to just draw a rought sketch
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I got that \[r = +or- (r*\sqrt{2\sin(\theta)}\]
sorry 4
4 * root(sin2(theta))
?
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The graph is the same for both positive and negative expressions
ohh ok. I think i get it
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