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Physics 19 Online
OpenStudy (anonymous):

A t=0 seconds, a cart is moving with a velocity of 10 cm/s and an acceleration of 4.0 (cm/s)/s. Assuming its acceleration stays at this value, what will its velocity be 7.0 seconds later?

OpenStudy (anonymous):

\[v _{f}=v _{i}+at\]

OpenStudy (anonymous):

So 10cm/s + (4.0 Cm/s/s)(7)

OpenStudy (anonymous):

Yes!

OpenStudy (anonymous):

Thank you so much!

OpenStudy (anonymous):

No problem!

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