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(cos Θ − cos Θ)^2 + (cos Θ + cos Θ)^2
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i am pretty sure it is sin^2
bu ti just need another opinion
?
(cos theta - cos theta)^2= 0^2 (cos theta + cos theta )^2 = (2cos theta)^2
no, you just put that one..... and i said "?"
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\[(\cos \theta+\cos \theta)^2=\cos ^2\theta+2\cos ^2\theta+\cos ^2\theta=4\cos ^2 \theta\]
so what type of cos equations would equal sin?
and he is gone... ignore that last question...
wish i i knew how to give medals...
yes (2cos theta)^2 = 4 cos ^2 theta
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we have the Pythagorean identity cos^2 + sin ^2 =1 where cos^2 theta =1- sin^ theta
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