Question

What is the domain of the function?
h(x) = √3-x over (x+6)(x^2+1) *The square root includes the -x*

Answer 1

\[h(x) = \frac{ \sqrt{3-x} }{ (x+6)(x^2+1) }\]

Answer 2

you want the roots part to be defined in the real numbers,

Answer 3

3-x . should be greater than or equal to zero

Answer 4

So would it be (-infinity,3]