Question

help please

Answer 1

\[(x-2)dx/(x^2(x-1)^2)\]

Answer 2

so i did partial fraction and got x-2=(Ax+B)(x-1)^2 + C(x-1)x^2 + Dx^2

Answer 3

i let x=1 -1=D
x=0 -2=B
x=2 0=(2A-B) +4C -4D

Answer 4

there is something wrong and i wasn't able to find all the values

Answer 5

no i'm suppose to find it

Answer 6

I think there are only constants in the partial fractions

x - 2 A B C D
---- = --- + --- + --- + ----
x^2(x - 1)^2 (x -1) (x - 1)^2 x^2 x

Answer 7

you only write Ax + B if its a function degree 2 that 's prime like x^2 + 4

Answer 8

http://www.wolframalpha.com/input/?i=write+as+partial+fraction+%28x+-+2%29+%2F%5Bx%5E2%28x+-+1%29%5E2%5D

there you go

Answer 9

thank you i get it now

Answer 10

yw