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Mathematics 15 Online
OpenStudy (diana.xl):

help

OpenStudy (diana.xl):

http://i.imgur.com/mkuCfCL.png

OpenStudy (diana.xl):

i need help on b and c.

imqwerty (imqwerty):

so u factored the equation nd u got- (x-40)(x+45)=0 so either x-40=0 thus x=40 or x+45=0 thus x=-45 but x is the width and it cannot be negative so x=-45 is rejected so the answer is x=40.

OpenStudy (diana.xl):

thats for b right?

imqwerty (imqwerty):

yes

OpenStudy (diana.xl):

was my answer for a correct?

OpenStudy (diana.xl):

how about c?

imqwerty (imqwerty):

yes your answer for a was correct and m confused with the c ...what type of answer do we need to enter in c part? do we need to tell the length nd width ?

OpenStudy (diana.xl):

one sec.

imqwerty (imqwerty):

ok

OpenStudy (diana.xl):

http://prntscr.com/8iqfao look at my answer for c in this one, ganeshie8 helped me with it. i think it should be something like that

imqwerty (imqwerty):

ok wait a sec :)

OpenStudy (diana.xl):

ok :)

imqwerty (imqwerty):

u must add this to ur answer to part b after you write the way u got width- we found that width=40yards given area=3600square yards area of rectangular park=length*breadth 3600=length*40 dividing both sides by 40 we get- length=90yards answer for c part wuld be- since x represents the width, we discard -45. The width of park is 40yards and the length is 90yards.

OpenStudy (diana.xl):

Tysm :]

imqwerty (imqwerty):

no prlm :D

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