so u factored the equation nd u got-
(x-40)(x+45)=0
so
either
x-40=0 thus x=40
or
x+45=0 thus x=-45
but x is the width and it cannot be negative so x=-45 is rejected so the answer is x=40.
OpenStudy (diana.xl):
thats for b right?
imqwerty (imqwerty):
yes
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OpenStudy (diana.xl):
was my answer for a correct?
OpenStudy (diana.xl):
how about c?
imqwerty (imqwerty):
yes your answer for a was correct and m confused with the c ...what type of answer do we need to enter in c part? do we need to tell the length nd width ?
OpenStudy (diana.xl):
one sec.
imqwerty (imqwerty):
ok
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OpenStudy (diana.xl):
http://prntscr.com/8iqfao
look at my answer for c in this one, ganeshie8 helped me with it. i think it should be something like that
imqwerty (imqwerty):
ok wait a sec :)
OpenStudy (diana.xl):
ok :)
imqwerty (imqwerty):
u must add this to ur answer to part b after you write the way u got width-
we found that width=40yards
given area=3600square yards
area of rectangular park=length*breadth
3600=length*40
dividing both sides by 40 we get-
length=90yards
answer for c part wuld be-
since x represents the width, we discard -45. The width of park is 40yards and the length is 90yards.
OpenStudy (diana.xl):
Tysm :]
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