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Find the negative square root of 48
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Any answer choices?
no
Hmm the one I got is -6.9
Ok do you know how you would get that without using a calclutor?
I do not
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ok thanks
you could factor 48 into its prime factors 2*2*2*2 * 3 and look for "pairs" there are two pairs of "2's". "pull each pair out of the radical, and put only one of each out front: \[ \sqrt{2\cdot 2 \cdot 2 \cdot 2 \cdot 3}= 2\cdot 2 \sqrt{3} \] simplify 2*2 to 4 and we want the negative square root, so make it negative \[ -4 \sqrt{3} \] notice what we get if we multiply it by itself \[ -4 \sqrt{3} \cdot -4 \sqrt{3} = -4\cdot -4 \cdot \sqrt{3} \cdot \sqrt{3} \\ =16 \cdot 3 = 48 \]
ok thanks i think i understand now
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