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ex − 12e−x − 1 = 0 solve to 4 decimal places. please
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the x values are exponents
this? \[e^x-12e^{-x}-1=0\]
yes peachpi
Multiply through by \(e^x\). \(e^{2x}-12-e^x=0\) rearrange and factor \(e^{2x}-e^x-12=0\) \((e^x-4)(e^x+3)=0\)
hell yea that was right. I just solved for x, but e^x+3 is not in the domain
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