Please help...........
Suppose we start with unlimited supplies of a 20% h2so4 solution and of a 50% h2so4 solution. We combine x liters of the first with y liters of the second to produce 7 liters of a 40% h2so4 solution. What does x equal?
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OpenStudy (welshfella):
work in masses of pure sulphuric acid
the mass of acid in 40% solution is 7 * 10 * 40 = 2800g
OpenStudy (anonymous):
2.8?
OpenStudy (welshfella):
x liters of 20% contains 200x g
y liters of 50% = 500y g
OpenStudy (welshfella):
so
200x + 500y = 2800
OpenStudy (anonymous):
yea
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OpenStudy (anonymous):
whats next
OpenStudy (welshfella):
now we need to find y in terms of x. Note that the 50% solution i s 5/2 = 2.5 times as strong as the 20% So y liters of 50% = how many liters of 20%?
OpenStudy (anonymous):
where did u get the 5/2?
OpenStudy (welshfella):
the ratio of 50/20 = 2/2
OpenStudy (welshfella):
* 5/2
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OpenStudy (anonymous):
oh okay
OpenStudy (welshfella):
so y liters of 50% = 2.5x liters of 20%
OpenStudy (anonymous):
yea
OpenStudy (welshfella):
200x + 500*2.5x = 2800
solve for x
OpenStudy (anonymous):
1.93?
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OpenStudy (welshfella):
yes
OpenStudy (anonymous):
hmmmm it's supposed to be 2.33333333
OpenStudy (welshfella):
oh
yes I've gone wrong somewhere
OpenStudy (welshfella):
something wrong in my logic somewhere
OpenStudy (dumbcow):
set up 2 equations...
x + y = 7
20x + 50y = (40)(7)
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OpenStudy (welshfella):
yep thats the way
OpenStudy (anonymous):
hmmm and then plug it in huh? y=7-x
OpenStudy (dumbcow):
yes
OpenStudy (anonymous):
got it thanx
OpenStudy (welshfella):
yea thats an easier way to do it. I still can't see what i did wrong . Worrying !
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OpenStudy (welshfella):
i see now!
OpenStudy (welshfella):
200x + 500y = 2800
was correct
then next step was to replace y with 7 - x