Mathematics
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OpenStudy (anonymous):
How do I use a table to find the solution to 5x+3=23, 8a-10=38, and 1/2x-5=-1?
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OpenStudy (anonymous):
make a X and Y column. Place an number you want under the x value and work out the problem. The resulting answer is your Y value.
OpenStudy (anonymous):
Let's start with a zero under the x. What is 5*0?
OpenStudy (anonymous):
X Y
0
OpenStudy (anonymous):
? are you there?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
what is 5 times zero?
OpenStudy (anonymous):
0
OpenStudy (anonymous):
correct, so in your first problem it was
5*0+3
so what amount is left?
OpenStudy (anonymous):
3
OpenStudy (anonymous):
yes. So now you include that number in your table
X Y
0 3
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OpenStudy (anonymous):
How many numbers do you want you table to be?
OpenStudy (anonymous):
idk
OpenStudy (anonymous):
It doesn't matter i guess
OpenStudy (anonymous):
I guess we could do it up to 3
OpenStudy (anonymous):
Well, lets say 3 then.
Pick a new number, say 1
place the 1 under the x column and multiply the 5 by one and then add 3
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OpenStudy (anonymous):
you get 8
OpenStudy (anonymous):
yes, so place 8 under the Y value
Show me what the new table looks like
OpenStudy (anonymous):
X Y
0 3
1 8
OpenStudy (anonymous):
good job. Now for our third number lets do -1
tell me what answer you get
OpenStudy (anonymous):
-2?
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OpenStudy (anonymous):
good job.
What does your finished table look like?
OpenStudy (anonymous):
X Y
0 3
1 8
-1 -2
OpenStudy (anonymous):
That is correct. You have successfully completed your first table. Now do the same for the others.