Question

Vertical asymptotes occur at x values where a function is not defined. Explain why it makes sense that y=1/x+3 has a vertical asymptote at x=−3.

Answer 1

\(\bf \cfrac{1}{{\color{brown}{ x+3}}}\qquad x=-3\implies \cfrac{1}{{\color{brown}{ (-3)+3}}}\implies \cfrac{1}{{\color{brown}{ 0}}}\)

does it make sense to have a vertical asymptote at x = -3?

Answer 2

i still dont get how you did that