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OpenStudy (calculusxy):

MEDAL!!! In parallelogram ABCD above, if sides AB and AD have lengths as shown, that is the length of the altitude to side AD? (Figure will be drawn below)

OpenStudy (calculusxy):

|dw:1442968342905:dw|

OpenStudy (calculusxy):

@phi

OpenStudy (calculusxy):

@peachpi @zepdrix

OpenStudy (anonymous):

what do you mean by "that is the length of the altitude to side AD" in the first place?

OpenStudy (calculusxy):

i don't know what that exactly means... or else i wouldn't have asked this question :\

OpenStudy (anonymous):

dont you mean like how high above ground level is the parallelogram?

OpenStudy (anonymous):

or something like that?

OpenStudy (calculusxy):

maybe ( or are you referencing the height)?

OpenStudy (anonymous):

altitude is a reference to how high above or how low below ground/sea level

OpenStudy (anonymous):

great, i just figured it out and i hate it

OpenStudy (anonymous):

are you in trig rn?

OpenStudy (anonymous):

@calculusxy i think i figured it out if you werent paying attention

OpenStudy (calculusxy):

no i don't know trig very well, but i can work with sine, cosine, tangent (only the basics)

OpenStudy (anonymous):

thats what this is

OpenStudy (anonymous):

line BC is going to be ground level for this

OpenStudy (calculusxy):

i don't quite understand what you mean

OpenStudy (anonymous):

if i remember right your going to use cosine to find the distance from line BC to line AD, giving you your answer (its either cosine or sine, i dont remember them that well)

OpenStudy (anonymous):

|dw:1442980427600:dw|

OpenStudy (calculusxy):

@surjithayer Can you plz explain this to me more?

OpenStudy (anonymous):

thx show off

OpenStudy (anonymous):

basically multiply the sine of 60 degrees by 12 to get your answer

OpenStudy (anonymous):

h is altitude |dw:1442980656562:dw|

OpenStudy (anonymous):

\[\sin 60=\frac{ \sqrt{3} }{ 2 }\]

OpenStudy (anonymous):

i just said everything he put up there in a nice sentence without any complication

OpenStudy (calculusxy):

and how do i evaluate that @surjithayer

OpenStudy (anonymous):

\[h=12 \sin 60=12*\frac{ \sqrt{3} }{ 2 }=6\sqrt{3}\]

OpenStudy (anonymous):

i like how i always start it then someone else comes in and takes all the fricken credit that i actually did before they did -_-

OpenStudy (calculusxy):

oh okay ! but is there any simper way of doing it?

OpenStudy (anonymous):

and the perfect example is the one above

OpenStudy (jhannybean):

That's about the easiest way to do it with the given information.

OpenStudy (anonymous):

thx for saying i had no idea what im doing and that a person that does the exact same thing makes complete sense, can someone explain that one to me >:(

OpenStudy (anonymous):

i seriously think that letting someone finish there answer and explanation should be on the CoC

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