Question

Write down, but do not evaluate, an integral for the area of this shaded region.

Answer 1

im not that advanced in school yet i cant help here sorry

Answer 2

@whpalmer4 can you help

Answer 3

This means the upper half of this region can be given by the double integral
\[\int_0^{\pi/4}\int_0^{\cos2 t}r\,dr\,dt=\frac{1}{2}\int_0^{\pi/4}\cos^2t\,dt\]
How might you adjust the limits to account for the bottom half as well?