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What is the solution of log(2x – 6) 256 = 4? I just want to know how to do this.
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is 256 a power or multiplier?
multiplier
So your problem is: \(256\log(2x-6)=4\) ?
Oh wait xD... my problem is like...
\[\log_{2x-6} 256 = 4\]
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okay. remember the log rule: \(\large \log_x b=a \implies x^a=b\)
I have no idea what that means xD
\[\log_{(2x-6)}256 = 4 \implies (2x-6)^4 = 256\] Do you see how the formula works?
Yes, but how do I change that to the answer? (The answer is x = 5, I took the test, I just wanna know how to do it)
Alright
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to get rid of the 4rth power, you take the 4rth root from both sides o the equation.
\[(2x-6)^4=256\]\[\sqrt[4]{(2x-6)^4} = \sqrt[4]{256}\]\[2x-6=4\]\[2x=10\]\[x=5\]
Thank you, thats all i wanted haha, I already gave u a medal
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