Question

What value of B makes the expression, x^2 + Bx +64 a perfect square trinomial?



16


8


4


2

Answer 1

@imqwerty

Answer 2

my answer is 4.

Answer 3

u have-
\[x^2 +Bx+64\]\[x^2+\frac{ 2Bx }{ 2}+8^2\]

and the square of (a+b) when opened is ->a^2 +2ab+b^2
comparing it with what we have we just need to make B/2 as 8

so B/2=8
B=16

Answer 4

Thank u