A hare, pursued by a grey-hound is 24 of her own leaps ahead of him. While the hare takes 6 leaps, the grey-hound takes 7 leaps. 7 leaps of grey-hound is equal to 9 leaps of hare. In how many leaps will the grey-hound overtake the hare?

Question

imqwerty · Answer

ok :)
 let us assume that one leap of hare=1m
 
so we are given that 
7 leaps of hound=9 leaps of hare 
so 1leap of hound=9/7 leaps of hare 
so 1leap of hound=9/7m 

nd then lets assume that the hare makes one leap in 1 sec 
time taken by hare to take 6 leaps =6secs 
and 6sec=time taken by hound to make 7 leaps 

so the hound makes 7/6leaps per sec 
1 leap of hound=9/7m
 so in 1 sec hound travels 7/6 x 9/7 m=3/2m 
 speed of hare is 1m/sec
and speed of hound is 1.5m/sec

and hare is 24 of her own leaps ahead =24m 

so let the time taken by hound to capture the hare be t 
so distance travelled by hound=distance traveled by hare+24m 

1.5(t) = 1(t)+24
 0.5(t)=24
 t=24/0.5
 t=48secs 
hound makes 7/6 leaps per sec so leaps made in 48 secs=7/6 x 48 =56

anonymous · Answer

The given answer is 280 :/

anonymous · Answer

@imqwerty

imqwerty · Answer

:) lets recheck

anonymous · Answer

6sec=time taken by hound to make 7 leaps 

Can you explain this?

imqwerty · Answer

its given that when the hare makes  leaps the hound makes 7 leaps so
the time taken by hare to make 6 leaps=6sec=time taken by hound to make 7 leaps

anonymous · Answer

Okay. But we ain't getting the right answer.

anonymous · Answer

@imqwerty ?

imqwerty · Answer

umm...m searching for a mistake in my method..